11y^2=33y

Solution for 11y^2=33y equation:

11y^2=33y

We move all terms to the left:

11y^2-(33y)=0

a = 11; b = -33; c = 0;
Δ = b2-4ac
Δ = -332-4·11·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-33}{2*11}=\frac{0}{22}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+33}{2*11}=\frac{66}{22}
=3
$